Calculation: 6eypbv - 1

y-y1 =
k* (x-x1)

y-y1 = k* (x-x1) $y-y1$ = $k\cdot (x-x1)$

y = k* (x-x1)+y1 $y$ = $k\cdot (x-x1)+y1$

y = x* k- x1* k+y1 $y$ = $x\cdot k-x1\cdot k+y1$

y = k* x- k* x1+y1 $y$ = $k\cdot x-k\cdot x1+y1$