Calculation: maEfJh - 1
h_max =
| v0^2* sin(α)^2 |
| / ( 2* g) |
|
h_max =
$$h_{max}$$ = $$\frac{v0^{2}\cdot sin(\alpha)^{2}}{2\cdot g}$$
| v0^2* sin(α)^2 |
| / ( 2* g) |
h_max =
$$h_{max}$$ = $$\frac{sin(\alpha)^{2}\cdot v0^{2}}{2\cdot g}$$
| sin(α)^2* v0^2 |
| / 2/ g |
h_max =
$$h_{max}$$ = $$\frac{0.5\cdot sin(\alpha)^{2}\cdot v0^{2}}{g}$$
| 0.5* sin(α)^2* v0^2 |
| / g |