Calculation: ziAMB7 - 1
sin(α)+sin(γ) =
n2+n1
n2+n1
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sin(α)+sin(γ) = n2+n1$$sin(\alpha)+sin(\gamma)$$ = $$n2+n1$$
sin(α) = n2+n1-sin(γ)$$sin(\alpha)$$ = $$n2+n1-sin(\gamma)$$
α = arcsin((n2+n1-sin(γ)))$$\alpha$$ = $$arcsin((n2+n1-sin(\gamma)))$$
α = arcsin(n2+n1-sin(γ))$$\alpha$$ = $$arcsin(n2+n1-sin(\gamma))$$