Calculation: lF73jo - 1

h__max =

v0^²* sin(α)^²

/ ( 2* g)

h__max =

v0^²* sin(α)^²

/ ( 2* g)

$h_{max}$ = $\frac{v0^{2}\cdot sin(\alpha)^{2}}{2\cdot g}$

h__max =

sin(α)^²* v0^²

/ 2/ g

$h_{max}$ = $\frac{sin(\alpha)^{2}\cdot v0^{2}}{2\cdot g}$

h__max =

0.5* sin(α)^²* v0^²

/ g

$h_{max}$ = $\frac{0.5\cdot sin(\alpha)^{2}\cdot v0^{2}}{g}$